Matematika Sekolah Menengah Atas [tex]\huge\blue{I am Darui's 5th Raikage Who Is The Boss In Komugakure Village}[/tex]
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(3x+2x)³ = 1000
[tex]\huge\purple{x=?}[/tex]
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[tex] \red{ \rule{20pt}{200pt}}[/tex][tex] \blue{ \rule{20pt}{200pt}}[/tex][tex] \purpls{ \rule{20pt}{200pt}}[/tex]​

[tex]\huge\blue{I am Darui's 5th Raikage Who Is The Boss In Komugakure Village}[/tex]
________________________________

(3x+2x)³ = 1000
[tex]\huge\purple{x=?}[/tex]
________________________________
[tex] \red{ \rule{20pt}{200pt}}[/tex][tex] \blue{ \rule{20pt}{200pt}}[/tex][tex] \purpls{ \rule{20pt}{200pt}}[/tex]​

Penjelasan dengan langkah-langkah:

(3x + 2x)³ = 1.000

5x = ³√1.000

5x = ³√10³

5x = 10^3/3

5x = 10

x = 10 ÷ 5

x = 2

x = 2

Penjelasan dengan langkah-langkah:

[tex] \sf{(3x + 2x)}^{3} = 1.000 \\ \sf3x + 2x = \sqrt[3]{1.000} \\\sf5x = \sqrt[\cancel{3}]{ {10}^{\cancel{3}} } \\ \sf5x = 10 \\ \sf \: x = \frac{10}{5} \\ \sf \: x = 2[/tex]

Pembuktian :

[tex] \sf{(3x + 2x)}^{3} = 1.000 \\ \sf{(3(2) + 2(2))}^{3} = 1.000 \\ \sf{(6 + 4)}^{3} = 1.000 \\ \sf{10}^{3} = 1.000 \\ \sf1.000 = 1.000[/tex]

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